4^2-n=1/2048

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Solution for 4^2-n=1/2048 equation:



4^2-n=1/2048
We move all terms to the left:
4^2-n-(1/2048)=0
We add all the numbers together, and all the variables
-n+4^2-(+1/2048)=0
We add all the numbers together, and all the variables
-1n+16-(+1/2048)=0
We get rid of parentheses
-1n+16-1/2048=0
We multiply all the terms by the denominator
-1n*2048-1+16*2048=0
We add all the numbers together, and all the variables
-1n*2048+32767=0
Wy multiply elements
-2048n+32767=0
We move all terms containing n to the left, all other terms to the right
-2048n=-32767
n=-32767/-2048
n=15+2047/2048

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